KEYCLOAK-5352 Basic Auth fails if password contains a ':'
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e1af9f133f
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2 changed files with 5 additions and 5 deletions
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@ -71,11 +71,11 @@ public class BasicAuthRequestAuthenticator extends BearerTokenRequestAuthenticat
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AccessTokenResponse atr=null;
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try {
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String userpw=new String(Base64.decode(tokenString));
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log.debug("Username and password string for basic auth is: " + userpw);
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int seperatorIndex = userpw.indexOf(":");
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String user = userpw.substring(0, seperatorIndex);
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String pw = userpw.substring(seperatorIndex + 1);
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log.debug("user: " + user);
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log.debug("pw: " + pw);
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log.debug("Username for token is: " + user + ", password is: " + pw);
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atr = getToken(user, pw);
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tokenString = atr.getToken();
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} catch (Exception e) {
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@ -98,12 +98,12 @@ public class HttpBasicAuthenticator implements Authenticator {
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try {
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String val = new String(Base64.decode(credentials));
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log.debug("Username and password string is: " + val);
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int seperatorIndex = val.indexOf(":");
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if(seperatorIndex == -1) return null;
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if(seperatorIndex == -1) return new String[]{val};
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String user = val.substring(0, seperatorIndex);
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String pw = val.substring(seperatorIndex + 1);
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log.debug("user: " + user);
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log.debug("pw: " + pw);
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log.debug("Resolved username is: " + user + ", password is: " + pw);
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return new String[]{user,pw};
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} catch (final IOException e) {
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throw new RuntimeException("Failed to parse credentials.", e);
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